The Kepler Problem (Part 6)

In Part 4 we saw that the classical Kepler problem—the problem of a single classical particle in an inverse square force—has symmetry under the group of rotations of 4-dimensional space \text{SO}(4). Since the Lie algebra of this group is

\mathfrak{so}(4) \cong \mathfrak{su}(2) \oplus \mathfrak{su}(2)

we must have conserved quantities

\vec{A} = (A_1, A_2, A_3)

and

\vec{B} = (B_1, B_2, B_3)

corresponding to these two copies of \mathfrak{su}(2). The physical meaning of these quantities is a bit obscure until we form linear combinations

\begin{array}{ccl} \vec{L} &=& \vec{A} \vec{B} \\ \vec{M} &=& \vec{A} - \vec{B} \end{array}

Then \vec{L} is the angular momentum of the particle, while \vec{M} is a subtler conserved quantity: it’s the ecc...

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Published on July 25, 2025 19:00
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