Mathamania discussion

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Word Problems

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message 1: by Elaine (new)

Elaine (caladhiel) The number of blues was 50 greater than 5 times the number of reds. Also, the number of reds was 210 less than the number of blues. How many were red and how many were blue?


message 2: by Jin (new)

Jin | 22 comments blue=250, red=40


message 3: by Elaine (new)

Elaine (caladhiel) Yep! Why don't you post one now?


message 4: by Jin (new)

Jin | 22 comments ok........
um....
There is 10 marbles in a bag. 3 of them are red, 5 of them are blue and 2 are them are yellow. What is a possibility that Sandra will pick blue marbles two times in a row without putting back the marble in after she draws out the first one?









message 5: by Elaine (new)

Elaine (caladhiel) 2/9


message 6: by Elaine (last edited Jan 27, 2009 05:58PM) (new)

Elaine (caladhiel) At 1p.m. Chester left the roundup and began the 66-mile trip to Dodge City. At 2p.m. Marshal Dillon left Dodge City to meet Chester. Marshal Dillon's speed was twice that of Chester, and they met at 9p.m. How fast did each man ride?


message 7: by Gabby (new)

Gabby R. | 11 comments Chester = 8.25 mph
Marshal Dillon = 16.5 mph


message 8: by Elaine (new)

Elaine (caladhiel) Sorry, but no.


message 9: by Gabby (new)

Gabby R. | 11 comments I'm not sure I really understand. Did each ride halfway?


message 10: by Elaine (new)

Elaine (caladhiel) No, they didn't. It's a uniform motion problem: D1 + D2 = k. So just remember that, combined, the total distance 66 miles. :)


message 11: by Gabby (new)

Gabby R. | 11 comments Combined.... I might get it.


message 12: by Elaine (new)

Elaine (caladhiel) You can do it!!! =)


message 13: by Gabby (new)

Gabby R. | 11 comments You must have never seen me in math class.


message 14: by Gabby (new)

Gabby R. | 11 comments Chester : 22 mph
Marshal Dillon : 44 mph


message 15: by Elaine (new)

Elaine (caladhiel) LOL!

Alas, but no. Um, try this:

RcTc + RdTd = 66


message 16: by Joon, Math genius (new)

Joon (JoonChang) | 67 comments Mod
So it is R times c, T times c, R times d, and T times d, right?



message 17: by Elaine (new)

Elaine (caladhiel) No. Sorry, I wasn't very clear. Rc=Rate of Chester. Tc=Time of Chester. Rd=Rate of Dillon. Td=Time of Dillon. You multiply them because rate x time equals distance (as shown in post 10). Does that make sense?


message 18: by Joon, Math genius (last edited Feb 07, 2009 03:43PM) (new)

Joon (JoonChang) | 67 comments Mod
I see. That makes the problem more clear. Give me a couple of mintues, I'll write back.


message 19: by Elaine (new)

Elaine (caladhiel) Okay!


message 20: by Elaine (last edited Apr 06, 2009 10:48AM) (new)

Elaine (caladhiel) *waiting for Joon to come back* It's been a bit more than a couple of minutes. =)


message 21: by Nicolle (new)

Nicolle | 43 comments lol


message 22: by Elaine (new)

Elaine (caladhiel) lol
How about you, Nicolle? Do you have the answer?


message 23: by Jin (new)

Jin | 22 comments i do not get the question....and where is the question anyway???


message 24: by Elaine (new)

Elaine (caladhiel) Here it is:

At 1p.m. Chester left the roundup and began the 66-mile trip to Dodge City. At 2p.m. Marshal Dillon left Dodge City to meet Chester. Marshal Dillon's speed was twice that of Chester, and they met at 9p.m. How fast did each man ride?


message 25: by Jin (new)

Jin | 22 comments hmmmmmmmmmmm.........*thinking*...........


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