Mathamania discussion


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message 1: by Joon, Math genius (last edited Jan 24, 2009 02:20PM) (new)

Joon (JoonChang) | 67 comments Mod
(52x + 32y)/(26x - 28y) Round to the nearest hundreth.
x=e and y=23.65

message 2: by Elaine (new)

Elaine (caladhiel) 2e - 1.14?

message 3: by Elaine (last edited Jan 25, 2009 11:47AM) (new)

Elaine (caladhiel) These are fun:

(x^3 - 4x + 2) / (-1 + x) = ?

(^ = to the power of)

message 4: by Joon, Math genius (new)

Joon (JoonChang) | 67 comments Mod
x^3 -3x -2. I think this is it.

message 5: by [deleted user] (new)

wow, that's complicated.
Do you do that in Algebra 1 or 2? Because if it's algebra 1, then my teacher has to teach us a lot in a short amount of time.

message 6: by Joon, Math genius (new)

Joon (JoonChang) | 67 comments Mod
I think this is in algebra 1 or pre algebra, but it isn't too hard.

message 7: by [deleted user] (new)

OK, then my teacher has quite a it to teach us this semester...

message 8: by Joon, Math genius (new)

Joon (JoonChang) | 67 comments Mod
Are you in algebra? If you are, then you are supposed to be learning this stuff.

message 9: by Elaine (new)

Elaine (caladhiel) Joon wrote: x^3 -3x -2. I think this is it.

Actually it's not. Remember that you are dividing x^3 - 4x + 2 by -1 + x. You also have to add 0x^2 in between the x^3 and -4x.

message 10: by Elaine (new)

Elaine (caladhiel) Yep, Miss Independent, I learned this in Algebra 1, so you should be learning it soon!

message 11: by Elaine (new)

Elaine (caladhiel) Oh, and Joon, did I get your's right?

message 12: by Joon, Math genius (new)

Joon (JoonChang) | 67 comments Mod
Oh. I thought you were dividing by 2 and -1. You need to put paranthesees around the ones you want to do first. Then you divide.

message 13: by Elaine (last edited Jan 25, 2009 11:47AM) (new)

Elaine (caladhiel) Okay, I'll edit, but it's only a one step problem.

message 14: by Joon, Math genius (new)

Joon (JoonChang) | 67 comments Mod
Thank you. Then it will make more sense.

message 15: by [deleted user] (new)

yeah, I'm in Algebra, but we do have to do a little bit of easier right now to prepare us for the 7th and 8th grade taks test (Texas Assessment of Knowledge and Skills).

message 16: by Joon, Math genius (new)

Joon (JoonChang) | 67 comments Mod
TAKS isn't hard, even thought I never make 100.

message 17: by [deleted user] (new)

it is easy. I have only gotten a 100 2 times, and the other 2 times i missed like 1.

message 18: by Elaine (new)

Elaine (caladhiel) Sooooooo? Did I get your problem right, Joon?

message 19: by Elaine (new)

Elaine (caladhiel) Elaine wrote: These are fun:

(x^3 - 4x + 2) / (-1 + x) = ?

(^ = to the power of)

So, does anyone have the answer to my problem? I could just post the answer and we could do a different one if you want.

message 20: by Jin (new)

Jin | 22 comments we are finding x??

message 21: by Elaine (last edited Jan 27, 2009 06:30PM) (new)

Elaine (caladhiel) No. You're just dividing x^3-4x+2 by -1+x. If you need any hints, I'll give you some!

message 22: by Priya (new)

Priya | 9 comments umm.. yall do easy problems...

message 23: by Ella (last edited Jan 28, 2009 07:13AM) (new)

Ella I don't think I've learned that yet, I'm not exactly too far in my algebra 1 book, I just finished my pre-algebra book (I'm in 8th grade, so I really not to worried about finishing the book this winter, I like doing math in the summer for some odd reason :P) Elaine, what does X equal? Is it three?

message 24: by Elaine (last edited Jan 28, 2009 01:02PM) (new)

Elaine (caladhiel) Ella, X doesn't have a set equality. (^ = to the power of). You will still have Xs in the final answer. Just set it up like a division problem. x^3+0x^2-4x+2 divided by x-1. It's actually quite simple and fun once you know what to do, but don't worry about not understanding it! You'll probably learn it towards the end of Algebra 1 (Division of Polynomials). =D

message 25: by Joon, Math genius (new)

Joon (JoonChang) | 67 comments Mod
Priya wrote: "umm.. yall do easy problems..."

Some of us are not like you Priya. Some of us like to take it easy and have fun. If you have something hard, prove it by showing me.

message 26: by Priya (new)

Priya | 9 comments hehehehe look at the geometry problems

message 27: by Elaine (last edited Jan 30, 2009 04:00PM) (new)

Elaine (caladhiel) Yes, you asked a hard problem, but you haven't answered any yet..., but nevermind because this is suppose to be about having fun not "who can do the hardest math".

message 28: by Joon, Math genius (new)

Joon (JoonChang) | 67 comments Mod
Fine. Give me a problem and I'll answer it.

message 29: by Priya (new)

Priya | 9 comments prove AA similarity
ha... try that!!!

message 30: by Elaine (new)

Elaine (caladhiel) *still waiting for someone to answer my question*

message 31: by Kate (last edited Jan 31, 2009 07:01PM) (new)

Kate | 4 comments x^2-x-3 r.-1 ??

Here's a fun one:
Let f(x)=x^2-9 and g(x)=2x+6. Find (fg)(-1).

message 32: by [deleted user] (new)


message 33: by Elaine (new)

Elaine (caladhiel) Sorry Kate, I didn't see your answer! You're really close, so I'll give it to you. The answer is:


You just forgot the to put the -1 over x-1. Good job!! =)

I got a different answer to the question you posted. My answer is:


or you could write it as: -2(x^3+3x^2-9x-27)


message 34: by [deleted user] (new)

okay. whoops.

message 35: by Elaine (new)

Elaine (caladhiel) Well, I don't know which one is correct, so I guess we'll just have to wait and see.

message 36: by [deleted user] (new)


message 37: by Kate (last edited Feb 07, 2009 03:30PM) (new)

Kate | 4 comments I thought you could write the answer to your problem either way, Elaine, but maybe not...

For mine, you need to put the function F(x)=2x+6 in for x in the function g(x)=x^2-9 and then put -1 in for x in the new equation.

message 38: by Elaine (last edited Feb 07, 2009 04:36PM) (new)

Elaine (caladhiel) Yep, you just used a remainder. I thought of that after I posted that. :)

What? Sorry, I'm confused (a common occurrence with me). :) So, did neither of us get it right?

message 39: by Kate (new)

Kate | 4 comments *Edit*

I made a mistake in my directions. You are NOT putting g(x) in for the x in f(x)! You are multiplying functions f(x) and g(x) and then putting -1 in for the "x"s. I'm really sorry. I hope I haven't confused anyone too badly!

message 40: by Nicolle (new)

Nicolle | 43 comments Are you all American?

message 41: by Elaine (new)

Elaine (caladhiel) Oh, okay, that makes much more sense. And don't worry about confusing me, Confused is my middle name! =D

Answer: -40!

That is a neat one!

message 42: by Elaine (new)

Elaine (caladhiel) Next problem:

Use the quadratic formula to solve:

message 43: by Elaine (new)

Elaine (caladhiel) Nicolle wrote: Are you all American?

Why do you ask?

message 44: by [deleted user] (new)

Can you teach me how to do that? The ^ puts it in exponents, right? I am confused...and yes, Nicolle, we're American. At least, I think.(I am!!)

message 45: by Joon, Math genius (new)

Joon (JoonChang) | 67 comments Mod
I am Korean and I am proud.

message 46: by Elaine (new)

Elaine (caladhiel) I guess we're a mix of nationalities! =)

message 47: by Elaine (new)

Elaine (caladhiel) Sarah, do you mean how to read the problem or how to use the quadratic formula?

message 48: by Nicolle (last edited Feb 09, 2009 11:59AM) (new)

Nicolle | 43 comments I was just curious as i think your school years are different. How old are you all and if your at school, what year are you in? x

message 49: by Joon, Math genius (new)

Joon (JoonChang) | 67 comments Mod
Well, I am in 8th grade and I am turning 14 in 3 days. I love math and love trying to figure it out.

Find the G.C.F of 5(x+2) + 23(x+2) Can't guarantee if it will come out right.

message 50: by P (new)

P (preethib) | 2 comments AAHHHH Everyone's turnong 14!

Happy Birthday ;P

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