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Can you do algebra?
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message 51:
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Wild for Wilde
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Nov 05, 2009 09:52AM

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He did -- but he deleted it right away for some reason. But honestly, this one was j..."
MATT!!! PUT IT BACK IN THE THREAD! I am very proud of your propensity and love for math. :)
You'd be surprised how fast it would probably come back to you Wild.
Can I do algebra?
Come back in fifteen years ago, and ask me again.
Come back in fifteen years ago, and ask me again.

Come back in fifteen years ago, and ask me again."
now that was funny

"ok...it's $10 for a dime bag and $5 for a nickle bag but i only got like $3.23 so i can get what...a joint and a blunt?"
That's what she said.
With all apologies to Sally Lou,
6x - 2 + 2x = -2 + 4x + 8
This is a fairly simple one Wild.
That is correct. See it came right back to you.
I would sign it, and then frame it. You never know when it might become a collectible. :-).
Please don't frame the gum Kevin.


cool teacher she was really tall though
nonetheless I had a good time
someone give me somethin' harder

:)
But what does it mean when "she" said it?
That cock wasn't hard enough, she wants more sex?
It's a weird thing to say: graphic, unnecessarily sexual, gross, and, I know you sigh as I say this, demeaning to women!
It's not funny.
That cock wasn't hard enough, she wants more sex?
It's a weird thing to say: graphic, unnecessarily sexual, gross, and, I know you sigh as I say this, demeaning to women!
It's not funny.


The only reason I changed majors in college (from Engineering to Journalism) was because engineering classes were so damn dull! The material was fun, but the people... good god, could they be any more boring? So the switch was on, though math became my minor.

Sorry
let me rephrase that for you
May I please have a difficult algebra problem/question?

Simplify the following:
3a^2b^3c^-2 / (a^-1b^2c)^3

In English, the problem is,
(Three times "a" squared) times (2 times "b" cubed) times (3 times "c" to the minus two) OVER quantity [("a" to the minus one) times ("b" squared) times ("c"):] cubed
Simple, really. :->
Phil wrote: "I loved math in school. Still do, many years later. A couple of months ago, an algebra II test randomly ended up on my lawn. First thing I did was bring it in and give it a go. :->
The only re..."
I am so envious. I didn't have the courage to change majors. I slogged out 6 years part/time in a business degree, with an accounting major. No wonder my brain has turned to mush. There wasn't a single subject that made it worth turning up. (The money is good though:-).)
The only re..."
I am so envious. I didn't have the courage to change majors. I slogged out 6 years part/time in a business degree, with an accounting major. No wonder my brain has turned to mush. There wasn't a single subject that made it worth turning up. (The money is good though:-).)
In comparison Engineering sounds fun!!! I loved maths at school too.

3a^2b^3c^-2 / (a^-1b^2c)^3 "
The answer is
3a^5 / b^3c^5
To solve this problem, you first deal with the exponent on the denominator. That makes the bottom of your fraction look like:
a^(-3) b^6 c^3
Then we just need to simplify the fraction.
The 3 can stay where it is.
To simplify the "a" exponent, remember that a^(-3) is the same as 1/a^3. That means you multiply the top quantity by a^3, which means adding the exponents. It ends up as 3+2=5.
For the "b" exponent, note that you have b^3 in the numerator and b^6 in the denominator. Doing the division gives you a quantity in the denominator of 6-3=3.
For "c", the negative exponent in the numerator becomes positive when moved to the denominator. Multiply by the quantity already there and you have 3+2=5.
Clear as mud, right? It really would be easier if GR would allow the superscript HTML tag.