Turing showed that indeed there is not. His argument was essentially the following. We first suppose that, on the contrary, there is such an algorithm.* Then there must be some Turing machine H which ‘decides’ whether or not the nth Turing machine, when acting on the number m, eventually stops. Let us say that it outputs the tape numbered O if it does not stop and 1 if it does: Here, one might take the coding of the pair (n, m) to follow the same rule as we adopted for the universal machine U. However this could run into the technical problem that for some number n (e.g. n = 7), Tn is not
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